36y^2-256=0

Solution for 36y^2-256=0 equation:

36y^2-256=0

a = 36; b = 0; c = -256;
Δ = b2-4ac
Δ = 02-4·36·(-256)
Δ = 36864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36864}=192$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-192}{2*36}=\frac{-192}{72}
=-2+2/3
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+192}{2*36}=\frac{192}{72}
=2+2/3
$